234a-1=368 dan 123b+2=478 berapakah nilai a x b
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Jawab:
6,0602
Penjelasan dengan langkah-langkah:
234a - 1 = 368
234a = 368 + 1
a = [tex]\frac{369}{234}[/tex] = 1, 57
123b + 2 = 478
123b = 478 - 2
b = [tex]\frac{476}{123}[/tex] = 3,86
a x b = 1, 57 x 3,86
= 6,0602
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